6x^(2/3)-7x^(1/3)-20=0

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Solution for 6x^(2/3)-7x^(1/3)-20=0 equation: 


x in (-oo:+oo)

6*x^(2/3)-(7*x^(1/3))-20 = 0

6*x^(2/3)-7*x^(1/3)-20 = 0

t_1 = x^(1/3)

6*t_1^2-7*t_1^1-20 = 0

6*t_1^2-7*t_1-20 = 0

DELTA = (-7)^2-(-20*4*6)

DELTA = 529

DELTA > 0

t_1 = (529^(1/2)+7)/(2*6) or t_1 = (7-529^(1/2))/(2*6)

t_1 = 5/2 or t_1 = -4/3

t_1 = -4/3

x^(1/3)+4/3 = 0

1*x^(1/3) = -4/3 // : 1

x^(1/3) = -4/3

( -4/3 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = 5/2

x^(1/3)-5/2 = 0

1*x^(1/3) = 5/2 // : 1

x^(1/3) = 5/2

x^(1/3) = 5/2 // ^ 3

x = 125/8

x = 125/8

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